(7/4a^2-3/2a+6)-(1/12a+3/4a+2)

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Solution for (7/4a^2-3/2a+6)-(1/12a+3/4a+2) equation:


a in (-oo:+oo)

(7/4)*a^2-((3/2)*a)-((1/12)*a)-((3/4)*a)-2+6 = 0

(7/4)*a^2+(-3/2)*a+(-1/12)*a+(-3/4)*a-2+6 = 0

7/4*a^2-7/3*a+4 = 0

DELTA = (-7/3)^2-(7/4*4*4)

DELTA = -203/9

DELTA < 0

a belongs to the empty set

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